Invert default selection from all to empty in selectors with multiple activated

[shaunwbell]

Is there a way to invert the default selections from all to empty when using a selector with multiple ?

I would like to build a filter that works by starting with no constraints and then applying new ones, rather than the other way around (all options selected by default). The list I would be putting into the dropdown is fairly large and I would rather select the one or two options I want at any given time as opposed to remove the 10's of options I don't.

My code snippet to build the selector is as follows

`
mooring_id = mooring_ids = list(df["MooringID"].unique()) #list of >100 options

<|{mooring_id}|selector|lov={mooring_ids}|multiple|label=Select the Mooring ID|dropdown|on_change=on_filter|class_name=fullwidth|>
`

[FlorianJacta]

You have initialized your selection to be all the selector values in your code. You can initialize it to None to solve your issue:

from taipy.gui import Gui 

mooring_ids = [f"Choice {i}" for i in range(100)]
mooring_id = None

md = "<|{mooring_id}|selector|lov={mooring_ids}|multiple|label=Select the Mooring ID|dropdown|on_change=on_filter|class_name=fullwidth|>"

def on_filter(state):
    print(state.mooring_id)

Gui(md).run()

[shaunwbell]

I did have to put it in an empty list but otherwise this is exactly what I wanted. Thanks

mooring_id = None

became

mooring_id = [None]

[FlorianJacta]

I guess you could just put mooring_id = [] then.