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huber loss equation in eager execution #148

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fsilavong opened this issue Sep 29, 2019 · 0 comments

fsilavong commented Sep 29, 2019

Hi, I was going through the assignments and realised that the huber loss equation was multiplied by two here:

stanford-tensorflow-tutorials/examples/04_linreg_eager.py

Line 43 in 51e53da

return t ** 2 if tf.abs(t) <= m else m * (2 * tf.abs(t) - m)

Any reason for that?

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