alignment.md

Section 1 / Alignment Within Structs

Overview

First, it is important to note that this section applies equally to both classes and structs. Ignoring methods (which are just functions connected to classes and structs), there is only a small difference between them.

In a C++ class, members default to private.

In a C++ struct, members default to public.

Classes, of course, do not exist in C.

Hereafter, we will use class and struct interchangeable.

In order to access data members of a struct you must be able to locate them relative to the start of the struct. If an instance of a struct begins at some address X, the first data member is also located at X so its relative offset from X is 0.

In our discussion of alignment, we'll frequently refer to the notion of offset.

Simple Rule

Data members exhibit natural alignment.

That is:

• a long will be found at addresses which are a multiple of 8.

• an int will be found at addresses which are a multiple of 4.

• a short will be found at addresses which are even.

• a char can be found anywhere.

Impact of the Simple Rule

Let's assume assume an int data member is placed properly at address some address, let's say 104. This is OK because 104 is a multiple of 4, the length of an int.

Suppose a long comes next. Does it start at location 108 or 112?

The answer is 112 even though this leaves a 4 byte gap between the end of the int and the beginning of the long. This is because the natural alignment of a long is upon addresses that are multiples of 8, the length of a long.

Sometimes, there are holes or gaps in a struct.

Higher level languages like C and C++ know this and produce the right code. Assembly language programmers have no obligation to stick to no stinkin' rules.

If they don't mind writing code that's buggy, that is.

Example 1

struct {
    long a;
    short b;
    int c;
};

Wrong:

Offset	Width	Member
0	8	a
8	2	b
10	4	c

Correct:

Offset	Width	Member
0	8	a
8	2	b
10	2	-- gap --
12	4	c

Demonstration:

Given this:

struct Foo {
    long a;
    short b;
    int c;
};

struct Foo Bar = { 0xaaaaaaaaaaaaaaaa, 0xbbbb, 0xcccccccc };

A hex dump will show:

aaaa aaaa aaaa aaaa bbbb 0000 cccc cccc

Notice the gap filled in which zeros. Note, if this were a local variable, the zeros might be garbage.

Example 2

Given this:

struct Foo {
    short a;
    char b;
    int c;
};

struct Foo Bar = { 0xaaaa, 0xbb, 0xcccccccc };

A hex dump will show:

aaaa 00bb cccc cccc

Notice there is only one byte of gap before the int c starts.

But, but, but - why are the zeros to the left of the b's?

This ARM processor is running as a little endian machine.

Diversion: Little Endian

Little endian means that within each unit of 2 (above a word), the least significant bytes come first.

In a little endian machine:

Type	Logical Contents	Actual Contents
long	aabbccddeeff0011	0011 eeff ccdd aabb

This shows that a long is 8 bytes:

aabbccddeeff0011

Transpose the two 4 byte groups:

eeff0011 aabbccdd

Transpose the 2 byte groups:

0011 eeff ccdd aabb

Type	Logical Contents	Actual Contents
int	44556677	6677 4455

This shows that an int is 4 bytes:

44556677

Transpose the two 2 byte groups:

6677 4455

The discussion on little endian is important if you are looking directly at the contents of memory, like when you are using gdb.