Dynamically set all properties of an extended class as not required

[PinkFromTheFuture]

In the code below, how I can have all the properties of EntityRequest as not required (required: false) without having to duplicate code?

I am extending the Entity model to define the EntityRequest model.
Both models should be the same, with the exception that all properties of EntityRequest should be not required.

The goal is to not repeat code. In other words, by dynamically making it so that every property of Entity will be considered in EntityRequest, without having to write code specifically for each of them. For example, the code of EntityRequest

@modelOptions({ schemaOptions: { timestamps: true } })
export class EntityRequest extends Entity {
  @prop({ required: false, unique: true })
  public legalEntityName!: string;

  @prop({ required: false, enum: ENUM_ENTITY_TYPE})
  public entityType!: string;
};

should be replaced by something like

@modelOptions({ schemaOptions: { timestamps: true } })
export class EntityRequest extends Entity {
  "for each property, set required: false"
};

---

import { prop, modelOptions, getModelForClass } from '@typegoose/typegoose';
import { ENUM_ENTITY_TYPE } from 'src/utils/enums'
import { countries } from 'src/utils/countriesList'
import { model } from 'mongoose'


@modelOptions({ schemaOptions: { timestamps: true } })
export class Entity {
  @prop({ required: true, unique: true })
  public legalEntityName!: string;

  @prop({ required: true, enum: ENUM_ENTITY_TYPE})
  public entityType!: string;

}

export const EntityModel = getModelForClass(Entity);


@modelOptions({ schemaOptions: { timestamps: true } })
export class EntityRequest extends Entity {
  @prop({ required: false, unique: true })
  public legalEntityName!: string;

  @prop({ required: false, enum: ENUM_ENTITY_TYPE})
  public entityType!: string;
};

export const EntityRequestModel = getModelForClass(EntityRequest);

[hasezoey]

no this is not supported by typegoose - you will have to "duplicate" code (also typegoose will likely never support such a thing)

if you really want to map properties, then you can try to manually build the schema and add a mapper in-between (or use a plugin to map it)

[MikeKoval]

@PinkFromTheFuture i faced same request, wondering how did you resolve it? did you duplicate code?
i am not a fun of duplicating code also, trying to use base abstract class and duplicate definition of required fields in inherited one

[PinkFromTheFuture]

Honestly I ended up migrating away from typegoose and mongoose all together and now I am back to relational databases while I call no-SQL databases "Glorified crap" =P

They have use-cases, but IMO, it should be very specific stuff, and not be used as basis for a whole platform.

[MikeKoval]

wondering what ORM do you use to work relational database? Prisma?

[PinkFromTheFuture]

Yeah, Prisma. But I believe that TypeORM would also be a solid choice.

…

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